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Calculate enthalpy of the reaction, F_(2)O(g)+H_(2)O(g) to O_(2)(g)+2HF(g) if the bond energies of O-F,O-H,H-F and O=O bonds are 44, 111, 135 and 119 kcal per mole respectively. |
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Answer» SOLUTION :We have to CALCULATE `DeltaH` of the reaction `F_(2)O(g)+H_(2)O(g) to O_(2)(G)+2HF (g) ` For reactants BOND energy of 2 MOLES of O-F bonds `=2xx44` kcal Bond energy of 2 moles of O-H bonds `=2xx111` kcal For products Bond formation energy of 1 mole of O=O bonds `=-119` kcal Bond formation energy of 2 moles of H-F bonds `=-2xx135` kcal Adding, we get `DeltaH` of the required equation, `DeltaH=2xx44+2xx111-119-2xx135=-79` kcal |
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