Calculate emf of the following cell at 25^(@)C: Fe|Fe^(2+)(0.001m)||H – InterviewSolution

1.	Calculate emf of the following cell at 25^(@)C: Fe\|Fe^(2+)(0.001m)\|\|H^(+)(0.01M)\|H_(2)(g)(1" bar")\|Pt(s) E^(@)(Fe^(2+)//Fe)=-0.44V,E^(@)(H^(+)//H_(2))=0.00V
Answer» SOLUTION :`E_(CELL)=0.44-(0.0591)/(2)"LOG"(0.001)/((0.01)^(2))=0.44-0.02955=0.41045V`

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