1.

Calculate emf of cell for the following reaction. Ni_((S))+2Ag^(+)(0.002M) to Ni^(+2)(0.160M)+2Ag_((S)) [where, E_(cell)^(@)=1.05V].

Answer»

`1.9142`
`9.142`
`0.9142`
`91.42`

SOLUTION :`0.9142`


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