1.

Calculate E_(cell) for Cr|Cr^(3+)||Cr^(3+)|Cr:

Answer»

`(0.028V)`
`(0.083)`
`(0V)`
`(0.125)`

SOLUTION : `E= (0.059)/(3) log ([Cr^(3+)]R.H.S)/([Cr^(3+)]L.H.S) = (0.059)/(3) log(1)/([0.04]) = 0.028 V`
`CU^(2+) (AQ) + 2E^(-) rightarrow Cu(s)`


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