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Calculate density of nacl its edge length of unit cell is 564pm and molar mass is 58.5 |
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Answer» HELLO dear______✌️✌️✌️ here's your answer__________________ ______________ given a = 564pm = 564*10-10cm fcc Z= 4 molecular mass of NACL (M)=58.44g/mol we know that density D= MZ/NA* a3 D= 588.44 g * 4/ 6.022*1023 * (564 * 10-10)3 DENSITY (D)= 0.216367 g/cm3 |
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