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Calculate DeltaH at 358 K for the reaction Fe_(2)O_(3)(s)+3H_(2)(g) to 2Fe(s)+3H_(2)O(l) Given that, DeltaH_(298)=-33.29 kJ "mole"^(-1) and C_(p) for Fe_(2)O_(3)(s),Fe(s),H_(2)O(l) and H_(2)(g) are 103.8, 25.1, 75.3 and 28.8 J/K "mole". |
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Answer» SOLUTION :`DeltaC_(p)=2xx25.1+3xx75.3-[103.8+3xx28.8]` `=85.9 "J/K mole"` We have, `(DeltaH_(2)-DeltaH_(1))/(T_(2)-T_(1))=DeltaC_(p)` ….(EQN. 9a) `(DeltaH_(358)-(-33290))/(358-298)=85.9` `DeltaH_(358)=-28136 "J/mole"` `=-28.136 "kJ/mole"`. |
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