1.

Calculate Delta_(r)G^(@) and log K_(c)for the following reaction at 298 K. 2Cr_((s))+Cd_((aq))^(3+)+33Cd_((s)){Given :E^(@)""_(Cell")=+0.34V,IF=96500Cmol^(-1)]

Answer»

Solution :`2Cr_((s))+3Cd_((aq))^(3+)+3Cd(s)`
`E^(@)cell =0.34V, IF=96500C//mol.`
`DELTAG^(@)=-NFE^(@)cell`
For this reaction , N = 6
`[{:(2Crto2Cr^(3+)+6E^(-)),(3Cd^(3+)+6e^(-)to3Cd):}]`
`DeltaG =-6 xx96500xx0.34`
`DeltaG=-196860J//molk_(c)`
`DeltaG=-2.303RT log k_(c)`
`logk_(c)""(-DeltaG)/(2.303xx8.314xx298)`
`logk_(c)=(+196860)/(2.303xx8.314xx298)`
`log k_(c)=34.5014`


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