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Calculate Delta G^@ for the following reaction.Ag^(+) (aq) + Cl^(-) (aq) to AgCl(s)Given Delta G_f^@ (AgCl) = - 109kJ //"mol"Delta G_f^@ (Cl^-) = -129 kJ/mol Delta G_f^@ (Ag^+) = 77 kJ/mol Represent the above reaction in the form of a cell. Also calculate E^@of the cell and find log K_(sp) of AgCl.

Answer»

SOLUTION :`(AG|AgCl, CL^(-) Ag^(+) | Ag) 0.59V, -10`


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