Calculate charge in columbs required 1 moles of water to oxygen

1.	Calculate charge in columbs required 1 moles of water to oxygen
Answer» Answer: a) 2H2O→4H+O2+4e− Q=4F =4×96500Cmol−1 =38600cmol−1 (b) ZN is oxidized and AG2O is REDUCED to Ag E0cell=E0Ag+/Ag−E0zn2+/zn =[0.344−(−0.76)V]V =1.104V AG0=−nFE0cell =−2×96500cmol−1×1.10V =−213×105Jmol−1

Answer»

Answer:

a) 2H2O→4H+O2+4e−

Q=4F

=4×96500Cmol−1

=38600cmol−1

(b) ZN is oxidized and AG2O is REDUCED to Ag

E0cell=E0Ag+/Ag−E0zn2+/zn

=[0.344−(−0.76)V]V

=1.104V

AG0=−nFE0cell

=−2×96500cmol−1×1.10V

=−213×105Jmol−1

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