1.

Calculate cell potential of electrochemical cell made up of Cr and Na. E_(Cr^(+3)//Cr)^(@)=-0.74V,E_(Na^(+)//Na)^(@)=-2.71V

Answer»

3.45 V
`-1.97` V
`-3.45V`
1.97 V

Solution :`E_(Cr^(+3)|Cr)^(@)=-0.74V,E_(NA^(+)|Na)^(@)=-2.71V`
`E_(cell)^(@)=E_("RED (cathode)")^(@)-E_("red (anode)")^(@)`
=-0.74+2.71=1.97 V


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