1.

Calculate |C.F.S.E| (mod value) is term of Dq. For complex ion [MnF_(6)]^(3-).

Answer»


SOLUTION :
`C.F.S.E.` VALUE`=-(3xx0.4Delta_(0))+(1xx0.6Delta_(0))=-0.6Delta_(0)=-6Dq`
`|CFSE|=6Dq`.


Discussion

No Comment Found