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Calculate Boyle temperature range for CO_(2) if its van der Waal's constants a and b are 3.592 atm "litre"^(2)" mole"^(2) and b =0.0427" litre mole"^(-1). |
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Answer» Solution :`T_(B) =(a)/(RB) =(3.592)/(0.0821xx0.0427)=1024.7K =752^(@)C` THUS, `CO_(2)` BEHAVES IDEAL in nature in the temperature range `752 pm t^(@)C` |
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