1.

Calculate and compare the energy released by :(a) Fusion of 1 kg of hydrogen deep within the sun, and (b) The fission of 1 kg of 92U235 in a fission reactor.

Answer»

In sun, 

Four hydrogen nuclei fuse to form a helium nucleus with the release of 26 MeV energy. 

∴ Energy released by fusion of 1kg of hydrogen :

E1 \(\frac{6\times 10^{23}\times 10^3}{4}\) × 26 MeV.

E1 = 39× 1026Mev

As,

Energy released in fission of one atom of 92U235 = 200 MeV.

∴ Energy released in fission of 1kg of 92U235 :

E2\(\frac{6\times 10^{23}\times 10^3}{235}\) × 26 MeV.

E2 = 5.1× 1026MeV

∴ \(\frac{E_1}{E_2}\) = \(\frac{39\times 10^{26}}{5.1\times 10^{-26}}\) 

= 7.65

i.e. energy released in fusion is 7.65 times the energy released in fission.



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