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calculate and compare the energies of two radiations ,one with a wavelength 400nm and other with 800nm |
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Answer» Calculation: E = hν h = Planck’s constant = 6.626 x 10(-34) J s ν = frequency λ = Wavelength = 400 nm C = Speed of LIGHT = 3 x 10(8) m/s ν = C / λ Substitute in the EQUATION, E = 6.626 x 10(-34) J s x 3 x 10(8) m/s / 400 x 10(-9) m E = 5 x 10(-19) J When λ = Wavelength = 800 nm E = 6.626 x 10(-34) J s x 3 x 10(8) m/s / 800 x 10(-9) m E = 2.5 x 10(-19) J Comparison: Since wavelength is inversely proportional to energy, the radiation with 400 nm has higher energy than the radiation with 800 nm. |
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