1.

Calculatate the mass of compound (molar mass = 256 g mol^(-1) be the dissolved in 75 g of benzene to lower its freezing point by0 .48 K(k_(f) = 5. 12 K kg mol ^(-1) .

Answer»


Solution :`W_(A)=75 G=0.075 KG, T_(f)=0.48K, M_(B)=256" g mol"^(-1)`
`K_(f)=5.12" K kg mol"^(-1)`
`W_(B)=(M_(B)xxDeltaT_(f)xxW_(A))/K_(f)=((256"g mol"^(-1))XX(0.48K)xx(0.075 kg))/((5.12" K kg mol"^(-1)))=1.8 g`


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