Calculae no. Of SO4 ions in 1.96 g of Cr2(SO4) 3

1.	Calculae no. Of SO4 ions in 1.96 g of Cr2(SO4) 3
Answer» EXPLANATION: SINCE Cr2(SO4)3 is a MOLECULE, it's oxidation number is 0. And the oxidation number of (SO4) is ALWAYS -2. Therefore, the oxidation number of Cr in Cr2(SO4)3 is +3.

Answer»

SINCE Cr2(SO4)3 is a MOLECULE, it's oxidation number is 0. And the oxidation number of (SO4) is ALWAYS -2. Therefore, the oxidation number of Cr in Cr2(SO4)3 is +3.

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Calculae no. Of SO4 ions in 1.96 g of Cr2(SO4) 3​

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Calculae no. Of SO4 ions in 1.96 g of Cr2(SO4) 3