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Calcuim phosphide (Ca_3P_2) formed by reacting calcuim orthophosphate (Ca_3(PO_4)_2) with magnesium was hydrolsed by water. The evolved phosphine (PH_3) was burnt in air to yield phosphorus pentoxide (P_2O_5).reducingcalcuim phosphide. (At. Wt. Mg=24, P=31) Ca_3(PO_4)_2+Mg toCa_3P_2+MgO Ca_3P_2+H_2OtoCa(OH)_2+PH_3 PH_3+O_2toP_2O_5+H_2O MgO+P_2O_5tounderset("magnesium metaphosphate")(Mg(PO_3)_2) |
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Answer» `Ca_3(PO_4)_2+8Mgt OCa_3P_2+8MgO` `Ca_3P_2+6H_2Oto3Ca(OH)_2+2PH_2` `2PH_3+4O_2toP_2O_5+3H_2O` `MgO+P_2O_5toMg(PO_3)_2` moles of magnesium USED =0.8 moles moles of MgO formed =0.8 moles moles of `Ca_3P_2` formed 0.1 moles moles of `PH_3` formed=0.2 moles moles of `P_2O_5` formed =0.1 moles (LIMITING REAGENT) moles of `Mg(PO_3)_2=0.1` moles mass of `Mg(PO_3)_2=18.2` gram |
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