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Calcualte the volume of `Cl_(2)` gas (in ml) liberated at 1 atm 273 K when 1.74 gm `MnO_(2)` reacts with 2.19 gm HCl according to the following with % yeild 40. `MnO_(2) + 4HCl rightarrow MnCl_(2) + Cl_(2) + 2H_(2)O`A. 336mlB. 112mlC. 134.4mlD. 44.8ml

Answer» Correct Answer - C


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