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Calcualte the solubility of `M_(2)X_(3)` in pure water, assuming that neither kind of ion reacts with `H_(2)O`. The solubility product of `M_(2)X_(3), K_(sp) = 1.1 xx 10^(-23)`. |
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Answer» `A_(2)X_(3)hArr2A^(+3)+3X^(-2)` `{:(1,0,0),(1-s,2s,3s):}` `K_(sp)=[A^(+3)]^(2)[X^(-2)]^(3)` `(2s)^(2)xx(3s)^(3)` `=4s^(2)xx27s^(3)` `=108s^(5)=1.1xx10^(-23)` `s=((K_(sp))/(108))^(1//5)` `=((1.1xx10^(-23))/(108))^(1//5)=10^(-5)mol L^(-1)` |
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