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| 1. |
Calcualte the numberof unpaired electrons in the following gaseous ions : Mn^(3+) , Cr^(3+), V^(3+) and Ti^(3+) Which one of these is most stable in aqueous solution ? |
| Answer» Solution :`Mn^(3+) = 3d^(4) = 4` UNPAIRED ELECTRON, `Cr^(3+) = 3 d^(3) = 3`unpaired electrons, `V^(3+) = 3d^(2) = 2` unpaired electrons, `Ti^(3+) = 3d^(1) = 1` unpaired electron. `Cr^(3+) ` is most stable out OFTHESE sin aqueoussolution because it has half- FILLED `t_(2g)` level `(i.e., t_(2g)^(3))` discussed in unit . | |