1.

Calcualte the molarity of a solution containing 14 g of KOH in 750 mL of solution.

Answer»


Solution :`"Molaraity of solution (M)"=("Mass of NaOH/Molar mass")/("VOLUME of solution in lirtes")`
`"Mass of KOH =14g Molar mass of KOH"=56" G mol"^(-1)`
`"Voluem of solution"=56" g mol"^(-1)`
`"Volume of solution"=750mL=750/1000=0.75 L`
`"Molarity (M)"=((14g)//(56" g mol"^(-1)))/((0.75 g L))molL^(-1)=0.33 M`


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