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Calcualte the mass of sodium acetate (CH_(3)COONa) required to make 500 mL of 0.375 molar aqueous solution. Molar mass of sodium acetate is 82.0245 g mol^(-1). |
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Answer» Solution :0.375 M aqueous solution means that 1000 ML of the solution contain SODIUM ACETATE = 0.375 MOLE `THEREFORE"500 mL of the solution should contain sodium acetate"=(0.375)/(2)"mole"` Molar mass of sodium acetate = `82.0245gmol^(-1)` `therefore"Mass of sodium acetate acquired "=(0.375)/(2)" mole"xx"82.0245 g mol"^(-1)=15.380g.` |
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