1.

calcualate the amount of heat evolved when 500 cm^(3) of 0.1M HCl is mixed with 200 cm^(3) of 0.2 M NaOH.

Answer»

57.3kJ
2.865 kJ
2.292 kJ
0.573 kJ

Solution :`HCl+NaOHto NaCl+H_(2)O`
at t=0,
number of moles = `(500xx0.1)/1000 = (200xx0.2)/1000 `
=0.05 =0.04
during neutralisation of 1 MOLE of NaOH by 1 mole of HCl, heat ecolved = 57. 3 kJ
to neutralised 0.04 moles of NaOH by 0.04 molw of NaOH, heat evolved
`57.3 XX 0.04`
= 2.292 kJ


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