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CALCISE 15 Aind the breadth of the rectangle whose perimeter is 160 cm and whoselength is:(c) 56.5 cm(a) 25 cm(b) 60 cm |
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Answer» 2(l+b)=perimeter2(25+b)=16025+b=160/225+b=80b=80-25b=55 cm 2(length + breadth)= perimeter of rectangle2( 25 + b) = 160(25 + b) = 160/225 + b = 80b = 80 - 25 b = 55 cm Let the breadth be b.length =25 cmperimeter=160 cm160=2 (25+b)160=50+2b160-50=2b110=2b2b=110b=110/2b=52 cm b is a answer 60 cm.. Let the breadth be b.length =25 cmperimeter=160 cm160=2 (25+b)160=50+2b160-50=2b110=2b2b=110b=110/2b=52 cm (a) breadth of rectangle = (perimeter /2) - length = (160/2) - 25 = 80 - 25 = 55 cm (b) breadth of rectangle = ( perimeter /2) - length = (160/2) - 60 = 80 - 60 = 20 cm (c) breadth of rectangle = (perimeter /2) - length = (160/2)-56.5 = 80 - 56.5 = 23.5 cm 55cm. your answer 55cm right answer this question 52 is the correct ans hoga option C) 56.5 cm is the correct answer 55 is correct answer |
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