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Calcaulte the standard free energy change taking place in `H_(2)//O_(2)` fuel in which the following reactions occurs: (i) `O_(2)+4H^(+) to 4e^(-)to2H_(2)O,E^(@)=1.229V` (ii) `2H_(2)to4H^(+)+4e^(-),E^(@)=0.000V` |
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Answer» `E_(cell)^(@)=E_(O_(2)//H_(2)O)^(@)(Red)+E_(H_(2)//H^(+))^(@)(Ox)=1.229+0=1.229V` `DeltaG=-nFE_(cell)^(@)=-4xx96500xx1.229J=-474.4kJ`. |
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