1.

calcaulate the bond enthalpy of Xe - F bond as given in the equation , XeF_(4) (g) to Xe^(+)(g) + F^(-) (g) + f_(2)(g)+ F(g) Delta_(r)H= 292 kcal mol ^(-1) lonisation energy of Xe = 279 kcal mol ^(-1) bond energy (F--F) = 38 kcal / mol Electronaffinity of F = 85 kcal / mol

Answer»

8.5 kcal/MOL
34 kcal / mol
24 kcal / mol
none of these

Solution :`Delta_(R)H`= heat supplied- heat evoled
`292 = (x+ 279)-(38+85) , x= 34 kcal mol^(-1)


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