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CaF_(2) used in HF "prep"^(n) must be free from SiO_(2) . Explain |
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Answer» Solution :`CaF_(2)+H_(2)SO_(4)toCaSO_(4)+HF` If `SiO_(2)` prsent as impurity `{:(4HF+SiO_(2)SiF_(4)+2H_(2)O),(SiF_(4)+2HFtoH_(2)[SiF_(6)]):}}` Hence PRESENCE of one MOLECULE `SiO_(2)` Consumer 6 molecule of HF |
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