1.

Caculatethe ionic radius of a Cs^(+)ion, assuming that the cell edge length forCsCl is 0.4123nm and that the ionic radius of a Cl^(-) ion is0.81 nm

Answer»

`0.352` nm
`0.116` nm
`0.231` nm
`0.176` nm

Solution :CsCl has a bcc LATTICE. So `d_("body")=asqrt(3)`
or`d_("body")=SQRT(3)xx0.4123` nm `=0.7147` nm
Ionic RADIUS of`CS^(+)=0.3571-0.1761` nm


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