Caculate the weights of following1)0.1mole sucrose b)0.1 Na2Co33)0.5 m

1.	Caculate the weights of following1)0.1mole sucrose b)0.1 Na2Co33)0.5 mole Gyspum
Answer» ose is C12H22O11 molecular MASS = 342 1 mole = 342 G 0.1mole= X GX = 0.1 × 342 = 34.2 g 2) Na2CO3molecular mass= 106 1 mole = 106 g 0.1mole= x gx= 10.6 g 3) gypsum is CaSO4.2H2Omolecular mass = 1721 mole = 172 g 0.5mole= x gx = 0.5 × 172 = 86 g

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