1.

Ca(OH)_(2)+H_(3)PO_(4) rarr CaHPO_(4)+2H_(2)O the equivalent weight of H_(3)PO_(4) in the above reaction is

Answer»

21
27
38
49

Solution :The EQUIVALENT weight of `H_(3)PO_(4)=("molecular weight")/2`
`:'` MOLE wt of `H_(3)PO_(4)=3+31+64=98`
`:. 98/2=49`


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