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(c) The third term of a GP is 4. Find the product of its first five terms. |
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Answer» Let the common ratio be r.Let the terms be a, ar, a(r^2) , a(r^3) , a(r^4) and so on.Therefore, a(r^2)=4 (According to the question, the third term of the GP is 4).Product of the first five terms = a * ar * a(r^2) * a(r^3) * a(r^4)= (a^5) * (r^10)= [a(r^2)]^5= 4^5.= 1024. |
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