C(s)+O2(g)→CO2(g), ΔrH=−94.3 kcal/mol CO(g)+12O2(g)→CO2

1.	C(s)+O2(g)→CO2(g), ΔrH=−94.3 kcal/mol CO(g)+12O2(g)→CO2(g), ΔrH=−67.4kcal/mol O2(g)→2O(g), ΔrH=117.4Kcal/mol CO(g)→C(g)+O(g), ΔrH=230.6Kcal/mol Calculate: ΔrH for C(s)→C(g) in Kcal/mol
Answer» $C (s) + O_{2} (g) \to C O_{2} (g), Δ_{r} H = - 94.3 k c a l / m o l$ $C O (g) + \frac{1}{2} O_{2} (g) \to C O_{2} (g), Δ_{r} H = - 67.4 k c a l / m o l$ $O_{2} (g) \to 2 O (g), Δ_{r} H = 117.4 K c a l / m o l$ $C O (g) \to C (g) + O (g), Δ_{r} H = 230.6 K c a l / m o l$ Calculate: $Δ_{r} H f o r C (s) \to C (g) i n K c a l / m o l$

C(s)+O2(g)→CO2(g), ΔrH=−94.3 kcal/mol CO(g)+12O2(g)→CO2(g), ΔrH=−67.4kcal/mol O2(g)→2O(g), ΔrH=117.4Kcal/mol CO(g)→C(g)+O(g), ΔrH=230.6Kcal/mol Calculate: ΔrH for C(s)→C(g) in Kcal/mol

Answer»

$C (s) + O_{2} (g) \to C O_{2} (g), Δ_{r} H = - 94.3 k c a l / m o l$

$C O (g) + \frac{1}{2} O_{2} (g) \to C O_{2} (g), Δ_{r} H = - 67.4 k c a l / m o l$

$O_{2} (g) \to 2 O (g), Δ_{r} H = 117.4 K c a l / m o l$

$C O (g) \to C (g) + O (g), Δ_{r} H = 230.6 K c a l / m o l$

Calculate: $Δ_{r} H f o r C (s) \to C (g) i n K c a l / m o l$