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(c) On A PQR23. Find the largest and the smallest digit in the blank space of thegiven number. so that the number is divisible by 3.solution |
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Answer» Answer: Answer is 86724 Step-by-step explanation: _6724. The number is divisible by 3 if the sum of its digits is divisible by 3. Adding the digits of the given number, 6+7+2+4=19 If 2 is added to the above number then the number will BECOME 21 which is divisible by 3 and also, 2 is the SMALLEST number that can fill the MISSING space. Now, if 8 is added to the given number then the number will become 27 which is divisible by 3 and 8 is largest number that can make the given number divisible by 3. Therefore, the smallest number will be 2 which will FORM 26724 and the largest number will be 8 forming 86724. |
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