C + O2 ---------> CO2 2C + O2 --------> CO2 2CO + O2 -----> 2CO2 In the first reaction, why is there no change in the entropy? Shouldn't delta S be +'ve, because solid plus gas is going going product, that is gas, hence more random movement. IN 3rd equation, why is delta S negative again? Because shiudlnt it be positive, because co2 is a gas, and hence more random movement? this is actually my doubt from the ellinghem diagram, metallurgy

C + O2 ---------> CO2 2C + O2 --------> CO2 2CO + O2 -----> 2CO2 In

1.	C + O2 ---------> CO2 2C + O2 --------> CO2 2CO + O2 -----> 2CO2 In the first reaction, why is there no change in the entropy? Shouldn't delta S be +'ve, because solid plus gas is going going product, that is gas, hence more random movement. IN 3rd equation, why is delta S negative again? Because shiudlnt it be positive, because co2 is a gas, and hence more random movement? this is actually my doubt from the ellinghem diagram, metallurgy
Answer» ^{C + O₂---------> CO_{2 2C + O}}_{2 --------> ^CO2 ^{2CO + O}2 ^{-----> 2CO}2 ^{In the first reaction, why is there no change in the entropy? Shouldn't delta S be +'ve, because solid plus gas is going going product, that is gas, hence more random movement. IN 3rd equation, why is delta S negative again? Because shiudlnt it be positive, because co2 is a gas, and hence more random movement? this is actually my doubt from the ellinghem diagram, metallurgy}}