1.

C_(("graphite"))+O_(2)(g)rarrCO_(2)(g), DeltaH=-94.05 kcal mol^(-1)C_(("diamond"))+O_(2)(g)rarrCO_(2)(g), DeltaH=-94.50 kcal mol^(-1)therefore

Answer»

`C_(("graphite"))rarrC_(("diamond")), DeltaH_(298 K)^(@)=-450 cal MOL^(-1)`
`C_(("diamond"))rarrC_(("graphite")), DeltaH_(298 K)^(@)=+450 cal mol^(-1)`
Graphite is the stabler allotrope
Diamond is harder than graphite

Solution :Heat energy is also INVOLVED when ONE allotropic form of an element in to another. Graphite is the stabler allotrope because the heat of transformation of
`C_(("diamond"))rarrC_(("graphite"))`.
(i) `C_(("dia"))+O_(2)(G)=CO_(2(g))DeltaH=-94.5 kcal`
(ii)`C_(("graphite"))+O_(2(g))=CO_(2(g))DeltaH=-94.0 k cal`
`DeltaH_("transformation")=-94.5-(-94.0)`
`=-0.5 kcal`.


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