C) Find the balue of k so that (x-1) is a factor ofthe polynomial5x²

1.	C) Find the balue of k so that (x-1) is a factor ofthe polynomial5x² + 4.8² - 6x + 2k
Answer» Answer: -11.02 Step-by-step explanation: We will apply factor theorem here x-1 = 0 , so x = 1 Now , let us replace x by 1 in the POLYNOMIAL 5(1) + 23.04 -6(1) +2k = 0 (then only the number WOULD be a factor) 22.04 + 2k = 0 2k = -22.04 K = -11.02 ∴ VALUE of k = -11.02

C) Find the balue of k so that (x-1) is a factor ofthe polynomial5x² + 4.8² - 6x + 2k

Answer»

Answer:

-11.02

Step-by-step explanation:

We will apply factor theorem here

x-1 = 0 , so x = 1

Now , let us replace x by 1 in the POLYNOMIAL

5(1) + 23.04 -6(1) +2k = 0 (then only the number WOULD be a factor)

22.04 + 2k = 0

2k = -22.04

K = -11.02

∴ VALUE of k = -11.02

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C) Find the balue of k so that (x-1) is a factor ofthe polynomial5x² + 4.8² - 6x + 2k​

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C) Find the balue of k so that (x-1) is a factor ofthe polynomial5x² + 4.8² - 6x + 2k