1.

c) Calculate the pH of an aqueous solution obtained by mixing 50 ml of 0.2 M HCI with 50 ml 0.1 M" " NaOH.

Answer»

Solution :No. of moles of HCI `=0.2 xx50xx10^(-3)`
`=10xx10^(-3)`
No. of moles of NAOH `=0.1 xx50xx10^(-3)`
`=5xx10^(-3)`
No. of moles of HCI after MIXING
`=10xx10^(-3)-5xx10^(-3)`
`5xx10^(-3)`
after mixing total VOLUME `= 100` mL
`therefore` Concentration of HCI in moles per litre
`=(5xx10^(-3)"Mole")/(100xx10^(-3) L)`
`[H_3 O^+]=5xx10^(-2) M`
`pH=-log (5xx10^(-2))`
`=2-log5`
`=2-0.6990`
`=1.30`.


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