1.

C_(6)H_(5).^(14)COOH on heating with Na_(2)CO_(3) releases

Answer»

`CO_(2)`
`.^(14)CO_(2)`
`CO`
none of these

Solution :`C_(6)H_(5).^(14)COOH+NaHCO_(3)to C_(6)H_(5).^(14)COONa+CO_(2)+H_(2)O`


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