1.

C_(4)H_(10)O underset(H_(2)SO_(4))overset(K_(2)Cr_(2)O_(7))toC_(4)H_(8)O underset("warm")overset(I_(2)//NaOH)to CHI_(3) Here N is

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Solution :As `C_(4)H_(8)O underset("warm") overset(I_(2)//NAOH) to CHI_(3)`
So `C_(4)H_(8)O` should have `-underset(O)underset(||)C-CH_(3)` group.
`:. C_(4)H_(8)O` can be `CH_(3)CH_(2) - underset(O)underset(||)C-CH_(3)`
so , `C_(4)H_(10)O(N)` should be `CH_(3)CH_(2)underset(OH)underset(|)(CH)CH_(3)`


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