1.

C) < 20220(tan20°) (cot 20°)5 + 2 tan15º tan 45º. tan75° T ATT(cosec 70°)2 (sec 70°)2(a) 4(b) 2(C) 3(d) 1

Answer»

(tan20/cosec70)2+(cot20/sec70)^2+2tan15tan45tan75={tan(90-20)/cosec70}^2+{cot90-20)/sec70}^2+2(tan90-15)tan45 tan 75=(cot70/cosec70)^2 + (tan70/sec70) ^2+ 2(cot75 tan 45 tan75 )=(cos 70/sin70/1/sin70)^2 +(sin70/cos70/1/cos70) ^2+2(1×1)=(cos70+sin70)^2 +2=1+2=3...



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