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C_(2)H_(6)(g) + 3.5O_(2)(g) rarr 2CO_(2)(g) + 3H_(2)O(g) DeltaS_("vap") (H_(2)O,l) = "x"_(1)calK^(-1) (boiling point =T_(1)) DeltaH_(f)(H_(2)O,l) = "x"_(2) DeltaH_(f)(CO_(2)) = "x"_(3) DeltaH_(f)(C_(2)H_(6)) = "x"_(4) Hence , DeltaH for the reaction is- |
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Answer» `2"x"_(3) + 3"x"_(2)-"x"_(4)` `DeltaH_(f)(H_(2)O,g) = DeltaH_(f)(H_(2)O,I) + DeltaH_("vap") = "x"_(2) + "x"_(1)"T"_(1)` `DeltaH_("reaction") = 2DeltaH_(f) (CO_(2),g) + 3DeltaH_(f)(H_(2)O,g) - DeltaH_(f)(C_(2)H_(6),g)` `""=2"x"_(3) + 3("x"_(2) + "x"_(1)"T"_(1)) - "x"_(4)=2"x"_(3) + 3"x"_(2) + 3"x"_(1)"T"_(1) - "x"_(4).` |
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