1.

C^(14) is radioactive. The activity and the disintegration product are

Answer»

`BETA-`active, `._(7)N^(14)`
`alpha - " active, " ._(7)Be^(10)`
Positron active, `._(5)B^(14)`
`gamma-"active ", C^(14)`

Solution :`._(6)C^(14) RARR ._(7)N^(14) + ._(-1)e^(0), beta`-active


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