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By which one of the following working temperature the efficiency of a carnot engine obtained maximum ? |
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Answer» 100 K , 80 K `therefore` For getting maximum efficiency , the ratio of `T_2/T_1` MUST be minimum . From option (A) `T_2/T_1=80/100`=0.8 From option (B) `T_2/T_1=60/80=3/4`=0.75 From option (C) `T_2/T_1=20/40=1/2`=0.50 From option (D) `T_2/T_1=40/60 =2/3`=0.67 `therefore` The minimum value of `T_2/T_1` is in (C ) so efficiency obtained maximum |
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