1.

By what vertical velocity a piece of stone must be thrown,so as it may attain a maximum height of 1000m (g= 9.8m/s^2)​........answer is 140m/s...can u plzz tell me the solution!!!!!!​

Answer»

Answer:

Let u be the initial velocity and h be the maximum height attained by the stone.

V

1

2

=u

2

−2gh,

(10)

2

=u

2

−2×10×

2

h

100=u

2

−10h ....(i)

Again at height h,

v

2

2

=u

2

−2gh

(0)

2

=u

2

−2×10×h

u

2

=20h ... (II)

So, from Eqs. (i) and (ii) we have

100=10h

h=10m


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