By what acceleration the boy must go up so that 100 kg block remains stationary on the wedge. The wedge is fixed and is smooth.(g=10m//s^(2))

By what acceleration the boy must go up so that 100 kg block remains s

1.	By what acceleration the boy must go up so that 100 kg block remains stationary on the wedge. The wedge is fixed and is smooth.(g=10m//s^(2))
Answer» SOLUTION :For the BLOCK to remain STATIONARY, `T=Mg SIN theta=100xx10xxsin 53` `=100xx10xx(4)/(5)=800N` For man, `T-mg=ma` `T=m(g+a)rArr 800=50(10+a)a=6m//s^(2)`