1.

By remainder theorem find the remainder when p(x) divide by g(x), p(x)= x^3-6x^2+2x-4 ,g(x)= 11-3/2x

Answer»

<P>Equate G(X) to 0.

So, 11-3/2x=0

11=3/2x

(11×2)/3=x

22/3=x

Now, put this VALUE of x in p(x).

So, p(22/3)=(22/3)³-6×(22/3)²+2×22/3-4

=10648/27-6×484/9+44/3-4

=2224/27


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