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By passing a charge of 1930 through an aqueous solution of gold chloride, 1.314 g of gold was deposited. Find the oxidation state of gold. (Given atomic mass of Au =197 amu). |
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Answer» SOLUTION :1.314 g of gold is DEPOSITED on passing charge=1930 C 197 g of gold is deposited on passing charge`=((1930C))/((1.314g))xx(197 g)=289353 C=(289353)/(96500)=3F`. OXIDATION state of gold is `=+3` |
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