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By how much percent area is decreased if the radius of a circle is decreased by 30%? |
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Answer» Let the radius of the circle is r. Therefore, the area of the circle is \(\pi\)r2. After decreasing 30% radius of the circle, The actual radius of the circle is r – \(\frac{30}{100}r\) = r – 0.3r = 0.7 r. The area of the circle after decreasing = \(\pi\)(0.7r)2 = 0.49 \(\pi r\) 2. Decreased area = Area of circle before decreasing – Area of circle after decreasing = \(\pi r\)2 – 0.49\(\pi r\)2 = 0.51 \(\pi r\)2 = 51% × Area of circle before decreasing. Hence, 51% area is decreased if the radius of a circle is decreased by 30% |
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