1.

By how much percent area is decreased if the radius of a circle is decreased by 30%?

Answer»

Let the radius of the circle is r. 

Therefore, the area of the circle is \(\pi\)r2

After decreasing 30% radius of the circle, 

The actual radius of the circle is r – \(\frac{30}{100}r\) = r – 0.3r = 0.7 r. 

The area of the circle after decreasing = \(\pi\)(0.7r)2 = 0.49 \(\pi r\) 2

Decreased area = Area of circle before decreasing – Area of circle after decreasing 

= \(\pi r\)2 – 0.49\(\pi r\)2 = 0.51 \(\pi r\)2  

= 51% × Area of circle before decreasing. 

Hence, 51% area is decreased if the radius of a circle is decreased by 30%



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