1.

By giving three examples explain that "the exponenets of the concentration terms are same or not as their stoichiometric coefficients in the balanced chemical reaction.

Answer»

Solution :In the following balanced equation the stoichiometric co-efficient are expressedas EXPONENTS of the concentration.
Reaction (i)is the formation of `NO_(2)`
`2NO_((g))+O_(2(g))to2NO_(2(g))`
The differential form of this rate expression is given as
Rate =`-(d[R])/(dt)=k[NO]^(2)[O_(2)]`
The rate law is not theoretically but must be determined experimentally.So ,in the following reaction the VALUE of exponent is different and it is determined by experimental method.
(i)Reaction:`CHCl_(3)+Cl_(2)toCCl_(4)+HCl`
The differential form of this rate expression is
Rate =`-(d[R])/(dt)=k[CHCl_(3)][Cl_(2)]^((1)/(2))`
and `(1)/(2)` is exponent of `[Cl_(2)]` but it is not coefficient of `Cl_(2)` in reaction .
(ii)Reaction :`CH_(3)COOC_(2)H_(5)+H_(2)OtoCH_(3)COOH+C_(2)H_(5)OH`
In this reaction the rate expression is according on the base of experimental value as given
Rate=`-(d[R])/(dt)=k[CH_(3)COOC_(2)H_(5)][H_(2)O]^(0)` Thus ,`H_(2)O` act as a reactant in reaction but experuimentally it is determined that the rate of reaction does not depenf on `[H_(2)O]`
So ,rate law for any reaction cannot be predicted by merely looking at the balanced chemical equation i.e. theoretically but must be determined experimentally.


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