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By giving three examples explain that "the exponenets of the concentration terms are same or not as their stoichiometric coefficients in the balanced chemical reaction. |
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Answer» Solution :In the following balanced equation the stoichiometric co-efficient are expressedas EXPONENTS of the concentration. Reaction (i)is the formation of `NO_(2)` `2NO_((g))+O_(2(g))to2NO_(2(g))` The differential form of this rate expression is given as Rate =`-(d[R])/(dt)=k[NO]^(2)[O_(2)]` The rate law is not theoretically but must be determined experimentally.So ,in the following reaction the VALUE of exponent is different and it is determined by experimental method. (i)Reaction:`CHCl_(3)+Cl_(2)toCCl_(4)+HCl` The differential form of this rate expression is Rate =`-(d[R])/(dt)=k[CHCl_(3)][Cl_(2)]^((1)/(2))` and `(1)/(2)` is exponent of `[Cl_(2)]` but it is not coefficient of `Cl_(2)` in reaction . (ii)Reaction :`CH_(3)COOC_(2)H_(5)+H_(2)OtoCH_(3)COOH+C_(2)H_(5)OH` In this reaction the rate expression is according on the base of experimental value as given Rate=`-(d[R])/(dt)=k[CH_(3)COOC_(2)H_(5)][H_(2)O]^(0)` So ,rate law for any reaction cannot be predicted by merely looking at the balanced chemical equation i.e. theoretically but must be determined experimentally. |
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