1.

Butanal with dilute NaOH gives

Answer»

`CH_(3)CH_(2)CH_(2)UNDERSET(H)underset(|)overset(OH)overset(|)"C"CH_(2)CH_(2)CH_(2)CH_(2)OH`
`CH_(3)CH_(2)CH_(2)overset(O)overset(||)C"CHO"CH_(2)CH_(2)CHO`
`OH"C"CH_(2)CH_(2)CH_(2)CH_(2)CH_(2)CH_(2)CHO`
`CH_(3)CH_(2)CH_(2)underset(H)underset(|)overset(OH)overset(|)C-underset(CH_(3))underset(|)underset(CH_(2))underset(|)CHCHO`

Solution :`2CH_(3)-CH_(2)-CH_(2)-CHO+"DIL."NaOH to CH_(3)CH_(2)CH_(2)-underset(H)underset(|)overset(OH)overset(|)C-overset(CHO)overset(|)CH-CH_(2)-CH_(3)`


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